I'm sure you have some opinion contrary, but I respectfully disagree with the implication of your statement, if not the exact language.
The forces acting on the ball can have varying impact on ball flight at different times during it's trajectory. A ball hit extremely hard on a certain starting path will maintain that initial flight path due to the strength of that initial force, which will nullify the effect of competing forces. The ball will begin to slow down due to the effect of wind drag, and the other competing forces (i.e. spin) will be able to influence ball flight more. So it's perfectly reasonable that a ball hit extremely hard on a 10* launch angle with extremely high backspin and hook-spin will stay low to the ground for the first third of its trajectory, then as air resistance slows down the ball speed, the effect of the backspin will cause lift, while the sidespin will cause hook. It's always spinning at the same rate, and it is always moving up and to the right, but the severity of the climb and hook will change several times during the flightpath. As the spin lessens towards the end of flight, for example, the ball will straighten out, then drop out of the sky.