On the course I regularly play, there is a short par 4 (270 yards) with the whole left side starting at the tees until the green that is water, marked as a lateral water hazard. The fairway also have a slight angle from right to left (left is lower). So since I play left handed, if I hit a slice, it will end up in the water for sure. I usually simply re-tee the ball (since the hole is not that long so lost of distance is not so important when playing for fun) and hit 3 from the tee (it is suposed to be 3 right? ).
But, from my understanding, since it is a lateral water hazard, one of my option would be to drop the ball inside 2 club lengths where it entered the hazard, as long as it is not closer to the hole (since it entered sideway due to a slice + roll, it enters the hazard at least 200 yards out, well inside the 100 yards to the green marker). My problem is that the way it is setup, you have the water, then about 1-2 feet of rough and then the car path. On multiple spots along the hazard line, there is no way I can drop the ball. If I drop it in the rough, I end up both feet on the car path, if I drop it at the maximum 2 club length, the ball ends on the carpath.
So my question is, how exactly should I play this. Since there is no way my drop would be playable, should I take another 2 club length after the car path (as long as it is not closer to the hole) and drop it there? If I do this, it is almost guaranteed that I can have my ball and both feet on the fairway (no rough between car path and fairway) and have a clear short shot at the pin playing 3. It looks a lot easier to make a simple bogey (double bogey at worst) from there (playing 3 around 50 yards out from the fairway than re-teeing for 3 at 270 yards away).
Thanks for your help!