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Posted
I boguht a new Titleist Drtiver a few weeks ago and I was telling a friend that the Torq is 3.9. Its a regular flex shaft and he says if I sing too hard it may get some twist. I think my swing speed on my driver is in the mid 80's just curious if I should be concerned about the torq. My intentions is in the next few weeks is go to my LGS and have my swing speed tested and if I need to I may get the driver reshafted. Anyway thanks for advice on torq.

Steve

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Posted
if your swing speed is in mid 80's you will be fine torq is how much the shaft twists the higher the torq generally the more forgiving the shaft is basically you will be fine

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Posted
Torque is measured in degrees (and it should not be technically.) For shafts, it is a standard of a certain force applied at a 90 degree angle at a certain lever distance from the shaft, and then measuring the degrees of twist that result. I do not know the parameters used for the measurement, but the units are foot-pounds or newton-meters. Given a fixed amount of torque, the amount of twist in the shaft is measured in degreeds and called "Torque." The results are pretty narrow for steel shafts, about 2 degrees up to nearly 4 degrees. Graphite has a wider range of torque values (a little below 3 to up to 6 or 7, depending on shaft) but your shaft is not that bad, especially given your swing speed. Zero torque would probably not feel very good so a little torque is fine -- it is what we are used to feeling. If you are a high speed swinger or square the club late, too much torque is harder to handle and it feels mushy... plus you leave some shots out right. Generally, steel shafts have been favored in irons for their low torque, but graphite is catching up. In drivers, graphite has allowed lighter shafts, something not always desired in irons. Sorry -- maybe more info than was needed.

RC

 


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    • All great info. Thanks for the reply. 
    • Yea, it's more complicated than your high school projectile motion equations.  I am thinking it could increase under certain conditions. A gust of wind blowing in the same direction as the spin, causing more high and low pressure on the ball in a certain way that it increases the spin?  It has zero vertical velocity at its apex. So, it is all velocity caused by gravity for the vertical component.  Yea, landing angle is a big thing.  It is parabolic. Your apex is 90 yards in the air. A 30-yard elevated green is 1/3rd that height. At the apex, your vertical descent angle is zero, it should be horizontal. So, you are going from zero theta to let's say 45 degrees. Even if it was linear, let's say you're landing angle is close to 30 degrees. That is less than a driver and probably is significant.  Yea, it depends on how you hit it. Especially for downhill shots. If you hit a flighted shot, it might react more like a normal shot because of the lower launch and lower apex relative to your position. Versus a normal shot might come in at like 70 degrees, instead of 45 degrees.       
    • Wordle 1,553 3/6 ⬜🟨🟨🟨🟨 ⬜🟨🟩🟨🟨 🟩🟩🟩🟩🟩
    • Spin will decay slightly over time, but not by a lot. The horizontal portion of the velocity will also decay due to air resistance. The vertical component will be increasing since the ball is accelerating due to gravity (albeit that the spin is creating lift, which will counteract that some). Neither of those has much of an impact of how the ball will react. The biggest difference is the vertical land angle. The angle theta prime (not sure how to show that on here) will be shallower than theta. That means the ball will stop faster at theta than at theta prime. The other thing is because there is still a horizontal component to the velocity, it will carry less far at theta prime than at theta.  The effects of those two things work in opposite directions. Which one "wins" will depend on ground conditions, ball flight, spin, any necessary carry distances, etc. Fortunately the margins are fairly small so you can wing it with enough experience. The calculation of the carry distance change is what your range finder estimates when you have slope turned on.
    • So, I was looking at this image and wondered what the best way is to play your approach to an elevated green versus a lowered green. Is the spin and velocity profile at θ' much different than at θ? I don't know the physics of it but to my wee brain, it would seem that at θ' the spin would be higher but velocity lower. At θ the spin would seem to be lower but velocity higher since it has more time to fall from its peak where it would be zero. Even the image below is off visually since we know the arc of the ball flight isn't consistent throughout.    It's okay if you tell me I'm overthinking this. 😂  
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