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iacas
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Absolutely F=ma is the law. However, you can substitute the impact velocity for acceleration to calculate the impact force. For example the loading on a runway created by a plane when it lands.

Are we just making stuff up now?

F=ma is not at all an appropriate formula for calculating anything relating to ball speed from the driver. If I swing a club at a consistent 125 MPH the ball's still going to go somewhere despite "a" being zero. The ball deforms, the shaft flexes, the face flexes (a little)... you can't use such simple formulas to tell you much about the golf swing. Swing faster and, all else the same, the ball goes farther. Swing the same speed but optimize another item - launch angle or spin, perhaps - and the ball goes farther.

Erik J. Barzeski —  I knock a ball. It goes in a gopher hole. 🏌🏼‍♂️
Director of Instruction Golf Evolution • Owner, The Sand Trap .com • AuthorLowest Score Wins
Golf Digest "Best Young Teachers in America" 2016-17 & "Best in State" 2017-20 • WNY Section PGA Teacher of the Year 2019 :edel: :true_linkswear:

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I feel like im in science class LOL

In My Hank Haney IJGA Bag
Driver: FT Tour 9.5 w/ Aldila Voodoo Stiff
3 Wood: i15 15.5 w/ avixcore red stiff
Hybrids: Rescue 09 19, 22 w/ fujikara fit on stiff
Irons: 4 & 5 MP-52, 6-PW MP-58 w/ KBS Tour Stiff Wedges: MP T-10 52*, 58* w/ KBS Tour StiifPutter: Fastback 1 34 inBall: : Pro...

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I'll give the science lesson a shot. My undergraduate degree is in physics, and that was only 3 years ago, so I should be able to remember most of this stuff

When the clubhead strikes the ball, the ball is accelerated at a rate directly proportional to the force applied by the club (this is where F=ma comes from). From the physics standpoint, a more useful quantity for calculating ballspeed would be the "impulse" applied to a ball. The impulse applied to a ball is basically dependent on the amount of force applied to the ball (dependent on how fast you clean the club), and the amount of time that the force is applied (how long the club and ball are in contact with each other). Whatever this impulse turns out to be happens to equal the change in momentum of the ball. Momentum turns out to equal mass*velocity (p=m*v), so if you calculate the impulse on a ball, you can find the velocity of said ball.

So, I think Slicer and Dean both have valid arguments. F=ma is useful for calculating initial acceleration of the ball, and measuring the impulse is useful for measuring the initial velocity. But, the two are closely related. Back to the golf, though A 103 SS with a 163 ball speed seems a little high. That's a smash factor of 1.58 which is higher than most touring pros (higher than any I've ever heard of). If you could post a video of your swing, that'd probably be the best way to help you out. Or even better yet, set up a lesson with your local (qualified) golf pro and take a lesson.

What I play:

Driver: XLS Hibore 9.5* Fit-On Red (S)
Woods: Tour XPC 16* Graffaloy ProLite (S)
Hybrid: Exotics 3HIrons: Reid Lockhart 3-SWWedge: rac 60*Putter: a crappy $20 Academy putter (but it works!)

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If I swing a club at a consistent 125 MPH the ball's still going to go somewhere despite "a" being zero.

That seems to make sense, but how did you get to 125 without acceleration?

You're right that we need more than F=ma to get accurate ball speed, but when we are referring to clubhead speed, which produces ball speed, F=ma is a good place to start. With Trackman, we can optimize the club based on current launch, speed, and spin conditions to give us the ideal driver for our swing. I think you're going to see a bigger discussion on weighting in the future.. all based off F=ma. Its about trying to find the right mix for you: club weight, swing speed given different club weights... THEN launch and spin rates.
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I'll give the science lesson a shot. My undergraduate degree is in physics, and that was only 3 years ago, so I should be able to remember most of this stuff

Thanx for articulating that picrig. The intent in my original post was to illustrate the importance of having a good rhythm, aka tempo. Swingspeed or weight shifting alone won't do it, you need both. The closer these two are to each other at the time of impact the better the result. For me thats the art of the game.

Ping I15 Driver, Ping i20 3 Wood & i20 Hybrid 3 Iron
Mizuno MP60 4-PW Irons
Vokey Spin Milled 52, 56 & 60 Degree Wedges
Odyssey Black Putter
 

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When the clubhead strikes the ball, the ball is accelerated at a rate directly proportional to the force applied by the club (this is where F=ma comes from).

For the exact same club with the ball struck the exact same position of the clubhead, with the shaft flexing at the same exact angle, percentage, and distance... and so on, it's likely proportional, though not linearly so.

Thing is, change your swing speed by 10 MPH and you change the shaft flex, how much the clubface will flex, how long the ball will be accelerated by the clubface (i.e. how long it stays on the clubface), and so many other factors it's really nowhere near as simple as saying "F=ma." Yes, if "ma" is the ball we can calculate the end force translated into lateral movement of the ball, but force is also expended flexing the clubface, absorbed by the shaft, deforming the ball, introducing spin, etc. F=ma gives us only one component (admittedly likely the largest component) of the force delivered by the clubhead.
So, I think Slicer and Dean both have valid arguments.

Unfortunately, they do not, as the physics surrounding this type of complex collision are greatly affected by all sorts of external factors that the arguments aren't valid simply because, unless we want to bore the tears out of everyone and spend 10 hours typing out all the math, it's impossible.

Put a ball weighing the same, shaped the same, and hit it identically with a driver and the ball speed will depend on how soft the cover of the ball is, because that affects how much energy is wasted by deforming the ball. And it's not linear either - softer balls maximize lower swing speeds (greater ratio of ball speed to swing speed) while others maximize higher swing speeds. You can resort to generalizations, of course. A heavier club swung at exactly the same speed with the same conditions (angle of attack, shaft flex, etc.) will hit the ball farther. Yep. But let me give you a four pound driver and see if you can even get close to swinging at your normal speed. The same is true to some extent in smaller weight increments, and is a large part of the reason why "swing the lightest clubs you can control" is still the basic tenet of clubfitting. Would you rather be hit by a semi truck going 10 MPH or a VW Beetle going 60 MPH. The semi weighs a lot more than 6x the VW...
That seems to make sense, but how did you get to 125 without acceleration?

Through the impact zone it's quite possible to make contact with the ball without accelerating. Surely you aren't suggesting that acceleration at the top of your backswing or at any moment prior to making contact with the ball matters at all...

Why, it's even to hit a golf ball while decelerating. In that case the ball would, what, go backwards?
You're right that we need more than F=ma to get accurate ball speed, but when we are referring to clubhead speed, which produces ball speed, F=ma is a good place to start.

No it's not... the instantaneous measurement of the acceleration of the clubhead is pretty much irrelevant.

I think you're going to see a bigger discussion on weighting in the future.. all based off F=ma.

No, not based on F=ma. You'd be closer if you were citing K=0.5mvv. Far more relevant. And it helps to explain the VW/semi thing above. It's also why people still suggest you swing the lightest club you can control.

Erik J. Barzeski —  I knock a ball. It goes in a gopher hole. 🏌🏼‍♂️
Director of Instruction Golf Evolution • Owner, The Sand Trap .com • AuthorLowest Score Wins
Golf Digest "Best Young Teachers in America" 2016-17 & "Best in State" 2017-20 • WNY Section PGA Teacher of the Year 2019 :edel: :true_linkswear:

Check Out: New Topics | TST Blog | Golf Terms | Instructional Content | Analyzr | LSW | Instructional Droplets

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Iacas,

You seem to know your golf science. Great info.


I agree with you that F=ma is not the sole determinant, but I think that it will now be taken into consideration once the correct shaft frequency, loft, spin rate, weight, golf ball, personal trainer, mental coach etc... have been exhausted. There is a perfect mix between the weight of the head and the ball speed and I know players are already testing heavier clubs and adjusting equipment to get optimal readings from trackman.

The clubhead must accelerate to maintain shaft pressure. If A=0, we have decreased shaft pressure, and if its a negative (decelerating) it will produce bad launch angles but not make the ball go in the opposite direction. My theories are based on ideal launch conditions where a decelerating clubhead wont give consistent readings.
If the clubhead is not accelerating, it is decelerating or has reached a constant speed, which are 2 things that would kill shaft pressure and the shaft would kick. If A=0 at impact, the clubhead speed could potentially increase. I agree that the the exact acceleration at impact is not required however acceleration shows shaft pressure which is something that is not raw data on a machine...yet.

The VW/semi example is extreme. Would you rather get hit with a brick or a feather. In this case, I would rather take a feather at 60 than a brick at 10. Its not that simple because whether the light one is moving faster than the heavy one, they both moving fast and both within reasonable speeds, creating almost the same amount of force and energy. When I refer to a light club moving fast, I mean 11oz at 125mph and a heavy one weighing 13.5 oz and swinging at 115mph. Its not like the 60 mph difference with the cars.


Have you had experience with Trackman or any other launch device?
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I agree with you that F=ma is not the sole determinant, but I think that it will now be taken into consideration once the correct shaft frequency, loft, spin rate, weight, golf ball, personal trainer, mental coach etc... have been exhausted. There is a perfect mix between the weight of the head and the ball speed and I know players are already testing heavier clubs and adjusting equipment to get optimal readings from trackman.

No. Again, a (of the clubhead) doesn't matter. It's an irrelevant statistic. The only such "speed" vector/measurement that matters is ball speed. Maybe clubhead speed, but even then, ball speed is the better number.

Nobody cares how fast the clubhead or ball accelerates... it's ball speed that matters (as well as launch angle and spin).
The clubhead must accelerate to maintain shaft pressure. If A=0, we have decreased shaft pressure, and if its a negative (decelerating) it will produce bad launch angles but not make the ball go in the opposite direction.

You seem to have missed the point of my F=ma dissection as it relates to hitting a golf ball... It was stated earlier that F=ma mattered - it doesn't. Clubhead speed matters. It doesn't matter how quickly or slowly you arrive at the given clubhead speed at impact. It's that instantaneous clubhead speed that matters, not acceleration.

I don't care about shaft loading and that wasn't being discussed before.
The VW/semi example is extreme. Would you rather get hit with a brick or a feather.

That's even more extreme. I could tell you that I'd rather get hit with a brick going 5 MPH than a feather going 2000 MPH. Ever seen a straw embedded inches into a tree after it was blown a few hundred MPH in a tornado?

In this case, I would rather take a feather at 60 than a brick at 10. Its not that simple because whether the light one is moving faster than the heavy one, they both moving fast and both within reasonable speeds, creating almost the same amount of force and energy. When I refer to a light club moving fast, I mean 11oz at 125mph and a heavy one weighing 13.5 oz and swinging at 115mph. Its not like the 60 mph difference with the cars.

You seem to have, again, missed the point. A feather at 60 has nowhere near the energy of a brick at 10 because, despite only a 6x difference in speed, you're looking at thousands of times difference in their mass.

Simply put, faster clubhead speeds translate to more ball speed better than increasing the weight of the club. For every unit of energy you get out of an increase in mass, you get that much energy squared by increasing the speed. A 50g clubhead swung at 50 MPH will hit the ball nowhere near as far as a 25g clubhead swung at 100MPH. It is, again, why people suggest you should swing the lightest club you can control: because speed matters more than weight at maximizing distance. Speed loses its effectiveness when you start to mis-hit the ball. If for some reason, you're a bizarre golfer with relatively few fast-twitch muscles and/or limited flexibility, and you can swing a heavier club within the square root of the units of the loss of speed, clearly you'll get more distance there. Such a point exists for every golfer, but most will lose control before they reach such a point (I can't swing a 1g clubhead any faster than a 1g clubhead because I've reached a physical limit - but I can't control any clubhead that light, regardless). Additionally, 60 - 10 = 50, not 60.
Have you had experience with Trackman or any other launch device?

Of course.

Erik J. Barzeski —  I knock a ball. It goes in a gopher hole. 🏌🏼‍♂️
Director of Instruction Golf Evolution • Owner, The Sand Trap .com • AuthorLowest Score Wins
Golf Digest "Best Young Teachers in America" 2016-17 & "Best in State" 2017-20 • WNY Section PGA Teacher of the Year 2019 :edel: :true_linkswear:

Check Out: New Topics | TST Blog | Golf Terms | Instructional Content | Analyzr | LSW | Instructional Droplets

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Simply put, faster clubhead speeds translate to more ball speed better than increasing the weight of the club. For every unit of energy you get out of an increase in mass, you get that much energy

I have no disagreements with your arguements except in the narrow view. Its not in my best interest to try and swing faster. Doing that does not give me greater distance. In fact I loose distance because I'm not getting my weight behind the ball. The mass multiplier is greater than VV in this case.

Ping I15 Driver, Ping i20 3 Wood & i20 Hybrid 3 Iron
Mizuno MP60 4-PW Irons
Vokey Spin Milled 52, 56 & 60 Degree Wedges
Odyssey Black Putter
 

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"Of course?" I didn't know if you were a golfpro or someone who moderated a forum.

If you're telling me that clubhead speed is the only thing that matters and that force has nothing to do with it, I'll rest my case. If you can understand that its the force that the clubhead is providing into the back of the golf ball, I would like to hear your views. The more I think about it, the more its really the same thing. The speed of the club head is directly related to the force it can apply to another object.

If the smash factor is ball speed divided by clubhead speed, then how can we get a better smash factor with less clubhead speed? Its a ratio, so the answer is to increase ball speed and this is done through better club and shaft dynamics - which is why I brought it up. If ball speed is increased, perhaps due to a different golf ball, the we should see the smash factor go up with the same clubhead speed, right?
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If you're telling me that clubhead speed is the only thing that matters and that force has nothing to do with it, I'll rest my case.

I've never said anything of the sort, and at this point, this discussion no longer interests me.

How you got what you just said from what I said I have no idea.

Erik J. Barzeski —  I knock a ball. It goes in a gopher hole. 🏌🏼‍♂️
Director of Instruction Golf Evolution • Owner, The Sand Trap .com • AuthorLowest Score Wins
Golf Digest "Best Young Teachers in America" 2016-17 & "Best in State" 2017-20 • WNY Section PGA Teacher of the Year 2019 :edel: :true_linkswear:

Check Out: New Topics | TST Blog | Golf Terms | Instructional Content | Analyzr | LSW | Instructional Droplets

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crikey sore head


Scanned this so dont shoot me


F=MA

Totally irrelevant, what is relevant is the F at impact, then the number of variables as far as ultimate distance are concerned are pretty big.


I dont see the point of this thread!


Ironic that i posted on it.
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All this F=ma stuff is missing a huge point. Force maxes out much earlier in the swing than during or just before impact. Think a moment -- acceleration is what makes a club to go to a higher clubhead speed, so I am guessing that the maximum force could even be at the moment in the transition from backswing to forward swing. As a club head approached the ball, the shaft been through a loading stage and is starting to flex forward and down because Force is not increasing at the same rate any longer, it is actually decreasing. Icarus is correct in his general concepts.

The problem in golf is to not slow just prior to impact. It is great if you can be generating some level of force later in the swing, but it will not be much at all. Your job as a golfer is not to lose speed -- there is no way the club accelerates as much in the last foot or so of arc like it does earlier in the swing. If it did, the shaft would deflect back and the club face would be very open. This is a very misunderstood part of the swing. You will not find photographic evidence of huge gains in speed in the last few inches of clubhead motion before impact -- so there is very little force showing up at this point in time.

However, it is important to have weight transfer, body mass, and firm, turning positions through impact because if you did not, the inelastic colllision of the golf ball with the club head would lose a great deal more energy into a loose, non-resisting connection to your body. The momentum transfer and the energy loss would show up in more places throughout your body and club. Think of it as the difference between dropping a ball on a concrete surface versus a gel surface (a poor analogy at best.) You want the least amount of energy loss and momentum loss going into your body as possible. If at the last instant of time before impact, your body, hands, etc., were turned into jello, the club would not cause the ball to depart with the same speed. Conservation of momentum would show up all over the place in the wiggling jello and a much less firm lever arm attachment. The wild card in all this business of trying to use words to describe the physics is the shaft. The shaft is responding and distorting all over the place, and its response time to forces that deform it depend on its own particular design properties.

So I cannot with confidence say much at all about extremely precise models of hitting a golf ball. It is a huge order of magnitude more difficult problem than calculating the quantum mechanical ground state of the hydrogen atom, even with QED corrections for several decimal places out in the answer (and omitting entirely the gravitational field.)

RC

 

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This thread has gotten a little contentious. I wasn't attempting to "side" w/Dean or Slicer earlier, just try to kind of expound upon what I thought they were saying.

I think that Iacas has the most valid argument. What do we hear clubmakers talk about often? Their newest club "transfer energy more efficiently to the ball." The sole goal of the swing is to maximize the energy of the ball as it leaves the clubhead. Iacas, I definitely agree with you that this isn't a simple problem and is a very high-dimension problem. To actually solve the equations involved w/all variables involved would most likely require some tensor calculus. Alas, physicists do tend to oversimplify problems (it's what we do). But, I think you're right that the kinetic energy of the clubhead (K=0.5mv^2) is most relevant if you want to know the affect of the club on the ball. Energy is conserved in the ball/club/body system. The body dissipates some of the energy in the clubhead, and energy is also lost to other places (the sound of the clubhead striking the ball, heat, ball deformation, etc), but I think you've hit the nail on the head.

Anyway, unless we're going to write out equations and actually prove something throwing words and ideas around probably won't persuade anyone who either doesn't have a background of some sort in physics or who has already decided what they believe is the most important equation to the golf swing (which seems like a somewhat ridiculous statement anyway).

What I play:

Driver: XLS Hibore 9.5* Fit-On Red (S)
Woods: Tour XPC 16* Graffaloy ProLite (S)
Hybrid: Exotics 3HIrons: Reid Lockhart 3-SWWedge: rac 60*Putter: a crappy $20 Academy putter (but it works!)

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